| ⇦ | 
| ⇨ |
A bar magnet having a magnetic moment of 2 x 10⁴JT⁻¹ is free to rotate in a horizontal plane. A horizontal magnetic field B = 6 x 10⁻⁴T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60⁰ from the field is
Options
(a) 12 J
(b) 6 J
(c) 2 J
(d) 0.6 J
Correct Answer:
6 J
Explanation:
Work done
= MB (cos θ₁ – cos θ₂)
= MB (cos 0⁰ – cos 60⁰)
= MB (1 – 1/2) = 2 x 10⁴ x 6 x 10⁻⁴ /2 = 6 J
Related Questions: - In a diffraction pattern due to a singleslit of width a, the first minimum is observed
- The optical path of a monochromatic light is same if it goes through 4.0 cm
- If the volume of a block of aluminium is decreased by 1%, the pressure
- A bimetallic strip consists of metals X and Y. It is mounted rigidly at the base as shown
- In the Davisson and Germer experiment, the velocity of electrons emitted from the
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a diffraction pattern due to a singleslit of width a, the first minimum is observed
- The optical path of a monochromatic light is same if it goes through 4.0 cm
- If the volume of a block of aluminium is decreased by 1%, the pressure
- A bimetallic strip consists of metals X and Y. It is mounted rigidly at the base as shown
- In the Davisson and Germer experiment, the velocity of electrons emitted from the
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply