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A bar magnet having a magnetic moment of 2 x 10⁴JT⁻¹ is free to rotate in a horizontal plane. A horizontal magnetic field B = 6 x 10⁻⁴T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60⁰ from the field is
Options
(a) 12 J
(b) 6 J
(c) 2 J
(d) 0.6 J
Correct Answer:
6 J
Explanation:
Work done
= MB (cos θ₁ – cos θ₂)
= MB (cos 0⁰ – cos 60⁰)
= MB (1 – 1/2) = 2 x 10⁴ x 6 x 10⁻⁴ /2 = 6 J
Related Questions: - Current in a coil changes from 4 A to zero in 0.1 second and the emf induced is 100V
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Current in a coil changes from 4 A to zero in 0.1 second and the emf induced is 100V
- A magnetic needle suspended parallel to a magnetic field requires √3J of work
- A potentiometer circuit has been set up for finding the internal resistance of a given
- Bohr’s postulates quantizes
- If potential(in volts) in a region is expressed as V(x,y,z) = 6xy – y + 2yz,
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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