| ⇦ | 
| ⇨ |
A bar magnet having a magnetic moment of 2 x 10⁴JT⁻¹ is free to rotate in a horizontal plane. A horizontal magnetic field B = 6 x 10⁻⁴T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60⁰ from the field is
Options
(a) 12 J
(b) 6 J
(c) 2 J
(d) 0.6 J
Correct Answer:
6 J
Explanation:
Work done
= MB (cos θ₁ – cos θ₂)
= MB (cos 0⁰ – cos 60⁰)
= MB (1 – 1/2) = 2 x 10⁴ x 6 x 10⁻⁴ /2 = 6 J
Related Questions: - Changing magnetic fields can set up current loops in nearby metal bodies
- When a wire of uniform cross-section a, length l and resistance R
- A body is thrown with a velocity of 9.8 m/s making angle of 30° with the horizontal
- According to Bohr model of hydrogen atom, only those orbits are permissible
- Three identical spheres, each of mass 3 kg are placed touching each other
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Changing magnetic fields can set up current loops in nearby metal bodies
- When a wire of uniform cross-section a, length l and resistance R
- A body is thrown with a velocity of 9.8 m/s making angle of 30° with the horizontal
- According to Bohr model of hydrogen atom, only those orbits are permissible
- Three identical spheres, each of mass 3 kg are placed touching each other
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply