MENU

A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum

A 70 Kg Man Stands In Contact Against The Inner Physics Question

A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum of radius 3 m rotating about its vertical axis with 200 rev/min.The coefficient of friction between the wall and his clothing is 0.15.When the floor is suddenly removed, what is the minimum rotational speed of the cylinder to enable the man to remain stuck to the wall without falling (approximately)?

Options

(a) 5 rad/s
(b) 10 rad/s
(c) 15 rad/s
(d) 20 rad/s

Correct Answer:

5 rad/s

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. A bar magnet of moment of inertia I is vibrated in a magnetic field of induction
  2. The angular momentum of an electron is J. The magnitude of the magnetic moment
  3. The electron drift speed is small and the change of the electron is also small
  4. Dimensional formula for electrical resistance R is given by
  5. The friction of the air causes a vertical retardation equal to 10%

Topics: Laws of Motion (103)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*