| ⇦ | 
| ⇨ |
A 2 kg mass starts from rest on an inclined smooth surface with inclination 30° and length 2 m. How much will it travel before coming to rest on a frictional surface with frictional coefficient of 0.25?
Options
(a) 4 m
(b) 6 m
(c) 8 m
(d) 2 m
Correct Answer:
4 m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A ball is projected upwards from the foot of a tower. The ball crosses the top
- A disc of radius 0.1 m is rotating with a frequency 10 rev/sec in a normal magnetic
- A thin rod of length L and mass M is bent at its midpoint into two halves
- If in a nuclear fusion process, the masses of the fusing nuclei be m₁ and m₂
- A body of mass m is thrown upwards at an angle θ with the horizontal with velocity
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A ball is projected upwards from the foot of a tower. The ball crosses the top
- A disc of radius 0.1 m is rotating with a frequency 10 rev/sec in a normal magnetic
- A thin rod of length L and mass M is bent at its midpoint into two halves
- If in a nuclear fusion process, the masses of the fusing nuclei be m₁ and m₂
- A body of mass m is thrown upwards at an angle θ with the horizontal with velocity
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
v2=u2+2gsin30
v=root20
S=v2/2(mu)g
S=20/2*0.25*10
S=4m