6.02 x 10²° molecules of urea are present in 100 mL of its solution

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6.02 x 10²° molecules of urea are present in 100 mL of its solution. The concentration of the solution is

Options

(a) 0.01 M
(b) 0.001 M
(c) 0.1 M
(d) 0.02 M

Correct Answer:

0.01 M

Explanation:

M= (6.02 x 10²° x 1000) / (100 x 6.02 x 10²³)
=0.01 M

Related Questions:

1. Which of the following is a primary halide
2. Nitrobenzene gives N-phenylhydroxylamine by
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4. Number of isomers of C₄H₁₀ is
5. Which of the following is a Lewis acid

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)

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