| ⇦ |
| ⇨ |
6.02 x 10²° molecules of urea are present in 100 mL of its solution. The concentration of the solution is
Options
(a) 0.01 M
(b) 0.001 M
(c) 0.1 M
(d) 0.02 M
Correct Answer:
0.01 M
Explanation:
M= (6.02 x 10²° x 1000) / (100 x 6.02 x 10²³)
=0.01 M
Related Questions: - The total number of electrons present in all the p-orbitals of bromine is
- Terylene is used for making
- The oxidation states of S atoms in S₄O₆²⁻ from left to right respectively
- The pH value of 10⁻⁸ M HCl is
- The IUPAC name of (CH₃)₂CH – CH₂ – CH₂Br is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The total number of electrons present in all the p-orbitals of bromine is
- Terylene is used for making
- The oxidation states of S atoms in S₄O₆²⁻ from left to right respectively
- The pH value of 10⁻⁸ M HCl is
- The IUPAC name of (CH₃)₂CH – CH₂ – CH₂Br is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply