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6.02 x 10²° molecules of urea are present in 100 mL of its solution. The concentration of the solution is
Options
(a) 0.01 M
(b) 0.001 M
(c) 0.1 M
(d) 0.02 M
Correct Answer:
0.01 M
Explanation:
M= (6.02 x 10²° x 1000) / (100 x 6.02 x 10²³)
=0.01 M
Related Questions: - Acetaldehyde can not show
- The hybridised state of N in R₂NH is
- Which of the following acts as an oxidising as well as reducing agent
- The mixture of n-hexane and n-heptane is an example of
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Acetaldehyde can not show
- The hybridised state of N in R₂NH is
- Which of the following acts as an oxidising as well as reducing agent
- The mixture of n-hexane and n-heptane is an example of
- Ferrocene is an example of
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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