| ⇦ | 
| ⇨ |
100 mL each of 0.5 N NaOH, N/5 HCl and N/10 H₂SO₄ are mixed together. The resulting solution will be
Options
(a) acidic
(b) neutral
(c) alkaline
(d) None of these
Correct Answer:
alkaline
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Transition elements
- Arsenic containing medicine used for the treatment of syphilis, is
- Indicator used in the titration of oxalic acid and NaOH is
- The oxidation state of I in H₄IO₆⁻ is
- Which of the following is broad spectrum drug
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Transition elements
- Arsenic containing medicine used for the treatment of syphilis, is
- Indicator used in the titration of oxalic acid and NaOH is
- The oxidation state of I in H₄IO₆⁻ is
- Which of the following is broad spectrum drug
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Take out the normality of the base and both the acids.
NaOH- N×V
0.5×100=50
HCL- N/5×100=20
H2SO4- N/10×100=10
Total normality of the acids-20+10=30
50>30
Solution is alkaline.