| ⇦ |
| ⇨ |
Planar structure is shown by
Options
(a) CO₃²⁻
(b) BCl₃
(c) N(SiH₃)₃
(d) All of these
Correct Answer:
All of these
Explanation:
C in CO₃²⁻ and B in BCl₃ are sp²-hybridised thus acquire planar geometry. Although N in N(SiH₃)₃ is sp³-hybridised but the steric hindrance caused by three bulky groups make it planar for higher stability.
Related Questions: - 1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide
- HSO₄⁻ + OH⁻ → SO₄²⁻ + H₂O. which is correct about conjugate acid – base pair
- The colour of p-aminoazobenzene is
- When ethanal is treated with Fehling’s solution. it gives a precipitate of
- How much energy is released when 6 moles of octane is burnt in air
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Chemical Bonding and Molecular Structure
(86)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide
- HSO₄⁻ + OH⁻ → SO₄²⁻ + H₂O. which is correct about conjugate acid – base pair
- The colour of p-aminoazobenzene is
- When ethanal is treated with Fehling’s solution. it gives a precipitate of
- How much energy is released when 6 moles of octane is burnt in air
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply