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When light of wavelength 300 nm falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, light of wavelength 600 nm is sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is
Options
(a) (1:2)
(b) (2:1)
(c) (4:1)
(d) (1:4)
Correct Answer:
(2:1)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A metal bar of length L and area of cross-section A is clamped between two rigid
- Assertion(A) :The change in kinetic energy of a particle is equal to the work done
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- A solid sphere is rotating in free space.If the radius of the sphere is increased
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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