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When light of wavelength 300 nm falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, light of wavelength 600 nm is sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is
Options
(a) (1:2)
(b) (2:1)
(c) (4:1)
(d) (1:4)
Correct Answer:
(2:1)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wheel of mass 10 kg has a moment of inertia of 10 kgm² about its own axis
- B is doped in Si or Ge, then we will get
- A uniform electric field and uniform magnetic field are acting along the same
- Let A = i Acosθ +j B sinθ be any vector.Another vector B which is normal to A is
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Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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