| ⇦ | 
| ⇨ |
Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å. Another source S₂ is producing 1.02 x 10¹⁵ photons per second of wavelength 5100Å Then, (power of S₂) (power of S₁) is equal to:
Options
(a) 1
(b) 1.02
(c) 1.04
(d) 0.98
Correct Answer:
1
Explanation:
energy emitted/sec by S₁, P₁ = n₁ hc / λ₁
energy emitted/sec by S₂, P₂ = n₂ hc / λ₂
P₂ / P₁ = n₂ / n₁ . λ₁ / λ₂
= 1.02 x 10¹⁵ / 10¹⁵ . 5000 / 5100 = 1.0
Related Questions: - An electron is
- Thin uniform rod of length L, cross-sectional area A and density ρ is rotated
- The self-inductance of a choke coil is 10 mH. When it is connected with a 10 V DC source,
- In the Davisson and Germer experiment, the velocity of electrons emitted from the
- A metal rod of length l cuts across a uniform magnetic field B with a velocity v.
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electron is
- Thin uniform rod of length L, cross-sectional area A and density ρ is rotated
- The self-inductance of a choke coil is 10 mH. When it is connected with a 10 V DC source,
- In the Davisson and Germer experiment, the velocity of electrons emitted from the
- A metal rod of length l cuts across a uniform magnetic field B with a velocity v.
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply