| ⇦ |
| ⇨ |
The speed of an electron having a wavelength of 10⁻¹⁰ m is
Options
(a) 6.26×10⁶ m/s
(b) 5.25 x10⁶ m/s
(c) 7.25×10⁶ m/s
(d) 4.24×10⁶ m/s
Correct Answer:
7.25×10⁶ m/s
Explanation:
λ = h / momentum = h / mv
v = h / mλ = 6.6 × 10⁻³⁴ / (9 × 10⁻³¹) × 10⁻¹°
v = 7.25 × 10⁶ ms⁻¹
Related Questions: - The ratio of magnetic dipole moment of an electron of charge e and mass m
- Which of the following is or the property of a cathode ray
- The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye
- A straight conductor of length 0.4 m is moved with a speed of 7 ms⁻¹perpendicular
- The condition under which a microwave oven heats up a food item containing
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of magnetic dipole moment of an electron of charge e and mass m
- Which of the following is or the property of a cathode ray
- The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye
- A straight conductor of length 0.4 m is moved with a speed of 7 ms⁻¹perpendicular
- The condition under which a microwave oven heats up a food item containing
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

P=h/lamba…..1equ
P= momentum
H=Planck’s constant
Lamba= wavelength
And
P=MV…..2 equ
M= mass
V= speed
Put 2 in 1
MV=h/lamba
9.1×10^-31*v=6.6×10^-34/10^-10
By solving u get the value of v
V=0.725*10^7=7.25*10^6