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The speed of an electron having a wavelength of 10⁻¹⁰ m is
Options
(a) 6.26×10⁶ m/s
(b) 5.25 x10⁶ m/s
(c) 7.25×10⁶ m/s
(d) 4.24×10⁶ m/s
Correct Answer:
7.25×10⁶ m/s
Explanation:
λ = h / momentum = h / mv
v = h / mλ = 6.6 × 10⁻³⁴ / (9 × 10⁻³¹) × 10⁻¹°
v = 7.25 × 10⁶ ms⁻¹
Related Questions: - Maximum velocity of the photoelectron emitted by a metal is 1.8×10⁶ ms⁻¹.
- A metal bar of length L and area of cross-section A is clamped between two rigid
- The length of an elastic string is a metre when the longitudinal tension is 4N and b
- what is the electric potential at a distance of 9cm from 3nC?
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Maximum velocity of the photoelectron emitted by a metal is 1.8×10⁶ ms⁻¹.
- A metal bar of length L and area of cross-section A is clamped between two rigid
- The length of an elastic string is a metre when the longitudinal tension is 4N and b
- what is the electric potential at a distance of 9cm from 3nC?
- We get Balmer series when electron comes from
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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P=h/lamba…..1equ
P= momentum
H=Planck’s constant
Lamba= wavelength
And
P=MV…..2 equ
M= mass
V= speed
Put 2 in 1
MV=h/lamba
9.1×10^-31*v=6.6×10^-34/10^-10
By solving u get the value of v
V=0.725*10^7=7.25*10^6