| ⇦ | 
| ⇨ |
An electron revolves in a circle at the rate of 10¹⁹ rounds per second. The equivalent current is (e=1.6×10⁻¹⁹C)
Options
(a) 1.0A
(b) 0.2A
(c) 0.1A
(d) 2.0A
Correct Answer:
0.2A
Explanation:
Current I = qf
Given, q = 16 × 10⁻¹⁹ C and f = 10¹⁹
Therefore, I = 1.6 A
Related Questions: - A small angled prism of refractive index 1.4 is combined with another small angled prism
- 6Ω and 12Ω resistors are connected in parallel. This combination is connected
- The Kα X-ray of molybdenum has a wavelength of 71×10⁻¹² m. If the energy of a molybdenum
- The photoelectric threshold wevelength for potassium (work function being 2 eV) is
- A plane polarised light is incident normally on a tourmaline plate. Its E vector make
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A small angled prism of refractive index 1.4 is combined with another small angled prism
- 6Ω and 12Ω resistors are connected in parallel. This combination is connected
- The Kα X-ray of molybdenum has a wavelength of 71×10⁻¹² m. If the energy of a molybdenum
- The photoelectric threshold wevelength for potassium (work function being 2 eV) is
- A plane polarised light is incident normally on a tourmaline plate. Its E vector make
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply