| ⇦ | 
| ⇨ |
An electron revolves in a circle at the rate of 10¹⁹ rounds per second. The equivalent current is (e=1.6×10⁻¹⁹C)
Options
(a) 1.0A
(b) 0.2A
(c) 0.1A
(d) 2.0A
Correct Answer:
0.2A
Explanation:
Current I = qf
Given, q = 16 × 10⁻¹⁹ C and f = 10¹⁹
Therefore, I = 1.6 A
Related Questions: - A particle covers half of its total distance with speed v1 and the rest half distance
- Two beams of light having intensities I and 4I interfere to produce a fringe pattern
- A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
- Two particles P and Q start from origin and execute simple harmonic motion along X-axis
- A thermoelectric refrigerator works on
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle covers half of its total distance with speed v1 and the rest half distance
- Two beams of light having intensities I and 4I interfere to produce a fringe pattern
- A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
- Two particles P and Q start from origin and execute simple harmonic motion along X-axis
- A thermoelectric refrigerator works on
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply