Power dissipated in an LCR series circuit connected to an a.c source of emf ? is

⇦

⇨

Power dissipated in an LCR series circuit connected to an a.c source of emf ? is

Options

(a) ?ￂﾲ √ [ R² + ( L? – 1 / C?)² ] / R
(b) ?ￂﾲ [ R² + ( L? – 1 / C?)² ] / R
(c) ?ￂﾲR / √ [ R² + ( L? – 1 / C?)² ]
(d) ?ￂﾲR / [ R² + ( L? – 1 / C?)² ]

Correct Answer:

?ￂﾲR / [ R² + ( L? – 1 / C?)² ]

Explanation:

Power dissipated in series LCR;
P = IR = / (Z) R
= ?ￂﾲR / [ R² + ( L? – 1 / C?)² ]
where Z = √ R² + ( L? – 1 / C?)²
is called the impedance of the circuit.

Related Questions:

1. A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity
2. Dimensional formula for electrical resistance R is given by
3. A very small circular loop of radius a is initially (at t=0) coplanar and concentric
4. An open knife edge of mass 200g is dropped from height 5m on a cardboard
5. A solid sphere is rotating in free space.If the radius of the sphere is increased

Topics: Alternating Current (96)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends