| ⇦ | 
| ⇨ |
A current of 2A flows through a 2Ω resistor when connected across a battery. The same battery supplies a current of 0.5A when connected across a 9Ω resistor. The internal resistance of the battery is
Options
(a) 0.5Ω
(b) 1/3Ω
(c) 1/4Ω
(d) 1Ω
Correct Answer:
1/3Ω
Explanation:
Let the internal resistance of the battery be r. Then the current flowing through the circuit is given by
i = E / R + r
In first case, 2 = E / 2 + r …(i)
In second case, 0.5 = E / 9 + r … (ii)
From (i) & (ii), 4 + 2r = 4.5 + 0.5r
1.5r = 0.5
r = 1/3Ω
Related Questions: - In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second
- The resultant of two forces, one double the other in magnitude, is perpendicular
- Two resistors of resistances 2Ω and 6Ω are connected in parallel.
- Which one of the following statement is FALSE ?
- A dip needle vibrates in a vertical plane perpendicular to magnetic meridian. The time
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second
- The resultant of two forces, one double the other in magnitude, is perpendicular
- Two resistors of resistances 2Ω and 6Ω are connected in parallel.
- Which one of the following statement is FALSE ?
- A dip needle vibrates in a vertical plane perpendicular to magnetic meridian. The time
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply