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In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second is 4×10²⁰. If the energy released per fission is 250 MeV, then the total energy released in 10 h is (1 eV=1.6×10⁻¹⁹ J)
Options
(a) 576×10⁶ J
(b) 576×10¹² J
(c) 576×10¹⁵ J
(d) 576×10¹⁸ J
Correct Answer:
576×10¹² J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
- Two discs of moment of inertia l₁ and I₂ and angular speeds
- A ship A is moving westwards with a speed of 10 km/h and a ship B 100 km
- If the series limit of Lyman series for hydrogen atom is equal to the series limit
- A siren emitting sound of frequency 800 Hz is going away from a static listener
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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