| ⇦ |
| ⇨ |
Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth is (g=acceleration due to gravity at Earth’s surface)
Options
(a) 2π√2R/g
(b) 4√2√R/g
(c) 2π√R/g
(d) 8π√R/g
Correct Answer:
4√2√R/g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Three unequal resistors in parallel are equivalent to a resistance 1 Ω.
- A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string
- A wire having resistance 12Ω is bent in the form of an equilateral triangle.
- A filament bulb (500W,100V) is to be used in a 230V main supply. When a resistance
- The time period of a mass suspended from a spring is T. If the spring is cut into four
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three unequal resistors in parallel are equivalent to a resistance 1 Ω.
- A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string
- A wire having resistance 12Ω is bent in the form of an equilateral triangle.
- A filament bulb (500W,100V) is to be used in a 230V main supply. When a resistance
- The time period of a mass suspended from a spring is T. If the spring is cut into four
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply