⇦ | ⇨ |
Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth is (g=acceleration due to gravity at Earth’s surface)
Options
(a) 2π√2R/g
(b) 4√2√R/g
(c) 2π√R/g
(d) 8π√R/g
Correct Answer:
4√2√R/g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which of the following rods of same material undergoes maximum elongation
- Two beams of light having intensities I and 4I interfere to produce a fringe pattern
- A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
- A train of mass 2x 10⁵ kg has a constant speed of 20 m/s up a hill inclined
- According to Bohr model of hydrogen atom, only those orbits are permissible
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following rods of same material undergoes maximum elongation
- Two beams of light having intensities I and 4I interfere to produce a fringe pattern
- A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
- A train of mass 2x 10⁵ kg has a constant speed of 20 m/s up a hill inclined
- According to Bohr model of hydrogen atom, only those orbits are permissible
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply