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If a body is rolling on the surface, its total energy will be
Options
(a)(1/2) mv² – (Gm₁m₂/R)
(b) (1/2) mv² + (1/2) Iω²
(c) (1/2) mv² – (1/2) mR²ω²
(d) None
Correct Answer:
(1/2) mv² + (1/2) Iω²
Explanation:
Total energy = P.E. + K.E. of (linear motion + Rotation)
= 0 + (1/2) mv² + (1/2) Iω²
Total energy = (1/2) mv² + (1/2) Iω².
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A metal wire of circular cross-section has a resistance R₁. The wire is now stretched
- The displacement of an object attached to a spring and executing simple harmonic
- A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
- If wavelength of a wave is λ=6000 Å, then wave number will be
- Three capacitors 3μF,6μF and 6μF are connected in series to a source of 120V.
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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