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A nucleus disintegrates into two nuclear parts which have their velocities in the ratio 2 : 1. The ratio of their nuclear sizes will be
Options
(a) 2¹/³ : 1
(b) 1 : 3¹/²
(c) 3¹/² : 1
(d) 1 : 2¹/³
Correct Answer:
1 : 2¹/³
Explanation:
Law of conservation of momentum gives m₁v₁ = m₂v₂
Therefore, m₁/m₂ = v₁/v₂ = 1/2
We know that, R = R₀.A¹/³
Where R is radius of nucleus and A is mass number.
.·. (R₁/R₂) = [A₁/A₂]¹/³ = [m₁/m₂]¹/³ = (1/2)¹/³
⇒ (R₁/R₂) = 1 / (2¹/³)
⇒ R₁ : R₂ = 1 : 2¹/³
Related Questions: - The mass of a ⁷₃ Li nucleus is 0.042 u less than the sum of the masses of all its nucleons
- A stone of mass 1 kg tied to a light inexensible string of length L=10/3 is whirling
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The mass of a ⁷₃ Li nucleus is 0.042 u less than the sum of the masses of all its nucleons
- A stone of mass 1 kg tied to a light inexensible string of length L=10/3 is whirling
- When volume of a system is increased two times and temperature is decreased
- A body is moving in a vertical circle. The string must remain taut at the highest point
- The threshold frequency for a certain photosensitive metal is ν₀. When it is illuminated
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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