| ⇦ | 
| ⇨ |
A nucleus disintegrates into two nuclear parts which have their velocities in the ratio 2 : 1. The ratio of their nuclear sizes will be
Options
(a) 2¹/³ : 1
(b) 1 : 3¹/²
(c) 3¹/² : 1
(d) 1 : 2¹/³
Correct Answer:
1 : 2¹/³
Explanation:
Law of conservation of momentum gives m₁v₁ = m₂v₂
Therefore, m₁/m₂ = v₁/v₂ = 1/2
We know that, R = R₀.A¹/³
Where R is radius of nucleus and A is mass number.
.·. (R₁/R₂) = [A₁/A₂]¹/³ = [m₁/m₂]¹/³ = (1/2)¹/³
⇒ (R₁/R₂) = 1 / (2¹/³)
⇒ R₁ : R₂ = 1 : 2¹/³
Related Questions: - Two conducting spheres of radii 5 cm and 10 cm are given a charge of 15 μC each.
- The dimensions of universal gas constant are
- A parallel beam of fast moving electrons is incident normally on a narrow slit.
- Wave nature of light is verified by
- A ball is thrown vertically downwards from a height of 20 m with an initially
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two conducting spheres of radii 5 cm and 10 cm are given a charge of 15 μC each.
- The dimensions of universal gas constant are
- A parallel beam of fast moving electrons is incident normally on a narrow slit.
- Wave nature of light is verified by
- A ball is thrown vertically downwards from a height of 20 m with an initially
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply