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A meter stick of mass 400 g is pivoted at one end and displaced through an angle 60°. The increase in its potential energy is
Options
(a) 2 J
(b) 3 J
(c) 0 J
(d) 1 J
Correct Answer:
1 J
Explanation:
Change in potential energy = mg/(1/2) (1-cosθ)
Given: mass = 400g = 0.4 kg and angle = 60°
Therefore, ∆U = 0.4 × 10 × (1/2) × (1-cos 60°) = 1 J.
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Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A solid sylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms⁻¹
- When we close one slit in the young’s double slit experiment, then
- Three cells, each of e.m.f 1.5 V and internal resistance 1 ohm are connected in parallel
- A 1 µA beam of protons with a cross-sectional area of 0.5 sq.mm is moving with a velocity
- A particle is executing a simple harmonic motion. Its maximum acceleration
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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