| ⇦ | 
| ⇨ |
A person of mass 60 kg is inside a lift of mass 940 kg and presses the button on control panel.The lift starts moving upwards with an acceleration 1.0 m/s². If g = 10 ms⁻², the tension in the supporting cable is
Options
(a) 8600 N
(b) 9680 N
(c) 11000 N
(d) 1200 N
Correct Answer:
11000 N
Explanation:
Total Mass = (60 + 940) kg = 1000 kg
Let T be the tension in the supporting cable, then,
T =M (g+a)
⇒ T = 1000(10+1) =11000 N
Related Questions: - A block of mass m is placed on a smooth wedge of inclination θ
- Two charges placed in air repel each other by a force of 10⁻⁴ N. When oil is
- In a given reaction,
ᴢXᴬ → ᴢ+1Yᴬ → ᴢ-1Kᴬ⁻⁴ → ᴢ-1Kᴬ⁻⁴
- The half life of radioactive isotope ‘X’ is 50 years. It decays to
- In a given process on an ideal gas, dW=0 and dQ<0. Then for the gas
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A block of mass m is placed on a smooth wedge of inclination θ
- Two charges placed in air repel each other by a force of 10⁻⁴ N. When oil is
- In a given reaction, ᴢXᴬ → ᴢ+1Yᴬ → ᴢ-1Kᴬ⁻⁴ → ᴢ-1Kᴬ⁻⁴
- The half life of radioactive isotope ‘X’ is 50 years. It decays to
- In a given process on an ideal gas, dW=0 and dQ<0. Then for the gas
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply