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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
Options
(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero
Correct Answer:
Mv newton
Explanation:
F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- From a disc of radius R, a concentric circular portion of radius r is cut-out so
- A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string
- The force F acting on a particle of mass m is indicated by the force-time graph
- A particle is moving such that its position coordinates (x,y) are (2 m,3 m) at time
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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