| ⇦ | 
| ⇨ |
Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
Options
(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero
Correct Answer:
Mv newton
Explanation:
F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.
Related Questions: - Weber ampere per metre is equal to
- A block of mass m moving at a velocity v collides with another block of mass 2m
- which of the following can not be emitted by radioactive substances during their decay?
- One coolie takes 1 minute to raise a suitcase through a height of 2 m
- An aeroplane is flying horizontally with a velocity of 216 km/h at a height of 1960 m.
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Weber ampere per metre is equal to
- A block of mass m moving at a velocity v collides with another block of mass 2m
- which of the following can not be emitted by radioactive substances during their decay?
- One coolie takes 1 minute to raise a suitcase through a height of 2 m
- An aeroplane is flying horizontally with a velocity of 216 km/h at a height of 1960 m.
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply