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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
Options
(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero
Correct Answer:
Mv newton
Explanation:
F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The magnetic susceptibility of a material of a rod is 449. Permeability of vaccum
- A ship of mass 3 x 10⁷ kg initially at rest is pulled by a force of 5 x 10⁴ N through
- The area of cross-section of one limb of an U-tube is twice that of the other.
- A gramophone record is revolving with an angular velocity ?. A coin is placed at
- A potentiometer circuit has been set up for finding the internal resistance of a given
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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