| ⇦ | 
| ⇨ |
The position x of a particle with respect to time t along x-axis is given by x = 9t² – t³ where x is in metres and t in second. What will be the position of this particle when it achieves maximum speed along the +ve x direction?
Options
(a) 54 m
(b) 81 m
(c) 24 m
(d) 32 m
Correct Answer:
54 m
Explanation:
Speed v = dx/ dt = d/ dt (9t² – t³) = 18t – 3t² For maximum speed
dv/ dt = 0 ⇒ 18 – 6t = 0 ⇒ t= 3
⇒Xmax = 81 – 27 = 54
Related Questions: - The period of oscillation of a mass M suspended from a spring of negligible mass is T
- A juggler maintains four balls in motion,making each of them to rise
- A radio isotope X with a half life 1.4 x 10⁹ years decays to Y which is stable
- Two discs of same material and thickness have radii 0.2 m and 0.6 m.
- If λ₁ and λ₂ are the wavelengths of the first members of the Lyman and Paschen
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The period of oscillation of a mass M suspended from a spring of negligible mass is T
- A juggler maintains four balls in motion,making each of them to rise
- A radio isotope X with a half life 1.4 x 10⁹ years decays to Y which is stable
- Two discs of same material and thickness have radii 0.2 m and 0.6 m.
- If λ₁ and λ₂ are the wavelengths of the first members of the Lyman and Paschen
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply