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A motorcycle moving with a velocity 72 kmh⁻¹ on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 m,the acceleration due to gravity is 10 ms⁻².In order to avoid skidding, he must not bent with respect to the vertical plane by an angle greater than
Options
(a) θ = tan⁻¹(2)
(b) θ = tan⁻¹(6)
(c) θ = tan⁻¹(4)
(d) θ = tan⁻¹(25.92)
Correct Answer:
θ = tan⁻¹(2)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bodies of mass 0.25 kg each moving towards each other with velocity
- What is the difference between soft and hard X-ray?
- The damping force on an oscillator is directly proportional to the velocity.
- The instantaneous angular position of a point on a rotating wheel is given by
- Infinite number of masses, each 1 kg, are placed along the x-axis
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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