| ⇦ | 
| ⇨ |
The radius of orbit of a planet is two times that of the earth. The time period of planet is
Options
(a) 4.2 year
(b) 2.8 year
(c) 5.6 year
(d) 8.4 year
Correct Answer:
2.8 year
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A body initially at rest is moving with uniform acceleration a m/s²
- Copper and carbon wires are connected in series and the combined resistor is kept
- If a proton, a deuteron and an alpha particle, on being accelerated by the same
- ₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle
- Perfectly black body radiates the energy 18 J/s at 300K. Another ordinary body of e=0.8
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body initially at rest is moving with uniform acceleration a m/s²
- Copper and carbon wires are connected in series and the combined resistor is kept
- If a proton, a deuteron and an alpha particle, on being accelerated by the same
- ₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle
- Perfectly black body radiates the energy 18 J/s at 300K. Another ordinary body of e=0.8
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
By keplers third law (T1^2/T2^2)=(R1^3/R2^3)
so,
x^2/1^2=(2r)^3/r^3
x^2=8
x=2.8