| ⇦ |
| ⇨ |
The radius of orbit of a planet is two times that of the earth. The time period of planet is
Options
(a) 4.2 year
(b) 2.8 year
(c) 5.6 year
(d) 8.4 year
Correct Answer:
2.8 year
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An electron moves on a straight line path XY as shown. The abcd is a coil adjacent
- Lumen is the unit of
- If radius of the ₁₃Al²⁷ nucleus is taken to be Rᴀı, then the radius of ₅₃Te¹²⁵ nucleus
- A body under the action of a force F⃗ = 6i⃗–8j⃗+10k⃗, acquires an accelerationof 1 m/s². The mass of this body must be
- A particle moves with constant speed v along a circular path of radius r and completes
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electron moves on a straight line path XY as shown. The abcd is a coil adjacent
- Lumen is the unit of
- If radius of the ₁₃Al²⁷ nucleus is taken to be Rᴀı, then the radius of ₅₃Te¹²⁵ nucleus
- A body under the action of a force F⃗ = 6i⃗–8j⃗+10k⃗, acquires an accelerationof 1 m/s². The mass of this body must be
- A particle moves with constant speed v along a circular path of radius r and completes
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

By keplers third law (T1^2/T2^2)=(R1^3/R2^3)
so,
x^2/1^2=(2r)^3/r^3
x^2=8
x=2.8