| ⇦ | 
| ⇨ |
In Young’s double slit experiment, the slit seperation is 1 mm and the screen is 1 m from the slit. For a monochromatic light of wavelength 500 nm, the distance of 3rd minima from the central maxima is
Options
(a) 0.50 mm
(b) 1.25 mm
(c) 1.50 mm
(d) 1.75 mm
Correct Answer:
1.25 mm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A ball is dropped from the root of a tower of height h
- What is the Q-value of the reaction?
¹H+⁷Li→⁴He+⁴He
- An objective moves ,starting from rest through a resistive medium
- The potential energy of a simple harmonic oscillator when the particle is half way
- A particle of mass m is projected with a velocity v making an angle of 45°
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A ball is dropped from the root of a tower of height h
- What is the Q-value of the reaction? ¹H+⁷Li→⁴He+⁴He
- An objective moves ,starting from rest through a resistive medium
- The potential energy of a simple harmonic oscillator when the particle is half way
- A particle of mass m is projected with a velocity v making an angle of 45°
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply