| ⇦ | 
| ⇨ |
The total energy of an electron in the first excited state of hydrogen atom is about -3.4 eV. Its kinetic energy in this state is
Options
(a) 3.4 eV
(b) 6.8 eV
(c) -3.4 eV
(d) -6.8 eV
Correct Answer:
3.4 eV
Explanation:
KE. = |(1/2) P.E.|
But P.E. is negavite
.·. Total energy = |(1/2) P.E.| – P.E. = – P.E. / 2 = – 3.4 eV
.·. K.E. = + 3.4 eV
Related Questions: - The distance travelled by a particle starting from rest and moving
- Current in a coil changes from 4 A to zero in 0.1 second and the emf induced is 100V
- Four identical rods are joined to from a square. If the temperature difference
- A point source emits sound equally in all directions in a non-absorbing medium.
- In an unbiased p-n junction, holes diffuse from the p-region to n-region because of
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The distance travelled by a particle starting from rest and moving
- Current in a coil changes from 4 A to zero in 0.1 second and the emf induced is 100V
- Four identical rods are joined to from a square. If the temperature difference
- A point source emits sound equally in all directions in a non-absorbing medium.
- In an unbiased p-n junction, holes diffuse from the p-region to n-region because of
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply