⇦ | ⇨ |
The total energy of an electron in the first excited state of hydrogen atom is about -3.4 eV. Its kinetic energy in this state is
Options
(a) 3.4 eV
(b) 6.8 eV
(c) -3.4 eV
(d) -6.8 eV
Correct Answer:
3.4 eV
Explanation:
KE. = |(1/2) P.E.|
But P.E. is negavite
.·. Total energy = |(1/2) P.E.| – P.E. = – P.E. / 2 = – 3.4 eV
.·. K.E. = + 3.4 eV
Related Questions: - A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor.
- A simple pendulum oscillates in a vertical plane. When it passes through the mean
- A metal rod of length l cuts across a uniform magnetic field B with a velocity v.
- A man weighing 60 kg climbs a staircase carrying a 20 kg load on his hand
- A current of 5 A is flowing at 220 V in the primary coil of a transformer. If the voltage
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor.
- A simple pendulum oscillates in a vertical plane. When it passes through the mean
- A metal rod of length l cuts across a uniform magnetic field B with a velocity v.
- A man weighing 60 kg climbs a staircase carrying a 20 kg load on his hand
- A current of 5 A is flowing at 220 V in the primary coil of a transformer. If the voltage
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply