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10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be
Options
(a) 3 mol
(b) 4 mol
(c) 1 mol
(d) 2 mol
Correct Answer:
4 mol
Explanation:
H₂+ 0.5 O₂ → H₂O
10 g of hydrogen reacts with 64 g of oxygen
5 mol of hydrogen react with 2 mol of oxygen
In this reaction, oxygen is limiting reagent.
Hence amount of water produced depends on the amount of oxygen taken
0.5 mole of oxygen gives water = 1 mol
2 moles of oxygen gives water = 4 mol
Related Questions: - How many coulombs are required for the oxidation of 1 mole H₂O to O₂
- Which is purified by steam distillation
- The oxidation state of Cr in K₂Cr₂O₇ is
- Roasting is done in
- The standard electrode potential is measured by
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- How many coulombs are required for the oxidation of 1 mole H₂O to O₂
- Which is purified by steam distillation
- The oxidation state of Cr in K₂Cr₂O₇ is
- Roasting is done in
- The standard electrode potential is measured by
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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