| ⇦ |
| ⇨ |
How many coulombs are required for the oxidation of 1 mole H₂O to O₂
Options
(a) 3.86 x 10⁵ C
(b) 1.93 x 10⁵ C
(c) 4.825 x 10⁴ C
(d) 9.65 x 10⁴ C
Correct Answer:
1.93 x 10⁵ C
Explanation:
H₂O → H₂ + 1/2 O₂ mole. No. of electrons involved = 2 mole = 2 × 6.023 × 10²³. 1 mole of electronic charge = 96500 C. ⇒ 2 mole of electronic charge = 2 × 96500. = 1.93 × 10⁵ C.
Related Questions: - Which among the following is an extensive property of the system
- D(+)-glucose reacts with hydroxyl amine and yields an oxime.
- Ammonia gas dissolves in water to form NH₄OH.In this reaction water acts as
- Many transition metals and their compounds exhibit
- If n = 6, the correct sequence for filling of electrons will be:
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which among the following is an extensive property of the system
- D(+)-glucose reacts with hydroxyl amine and yields an oxime.
- Ammonia gas dissolves in water to form NH₄OH.In this reaction water acts as
- Many transition metals and their compounds exhibit
- If n = 6, the correct sequence for filling of electrons will be:
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply