| ⇦ | 
| ⇨ |
6.02 x 10²° molecules of urea are present in 100 mL of its solution. The concentration of the solution is
Options
(a) 0.01 M
(b) 0.001 M
(c) 0.1 M
(d) 0.02 M
Correct Answer:
0.01 M
Explanation:
M= (6.02 x 10²° x 1000) / (100 x 6.02 x 10²³)
=0.01 M
Related Questions: - Lanthanides and actinides resemble in
- The rate of reaction between two reactants A and B decreases by a factor of
- Which of the following will be most stable diazonium salt RN₂⁺ X⁻
- Chlorination of toluene in the presence of light and heat followed by treatment
- Which of the following statements is incorrect
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Lanthanides and actinides resemble in
- The rate of reaction between two reactants A and B decreases by a factor of
- Which of the following will be most stable diazonium salt RN₂⁺ X⁻
- Chlorination of toluene in the presence of light and heat followed by treatment
- Which of the following statements is incorrect
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply