| ⇦ | 
| ⇨ |
A particle executes simple harmonic oscillations with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
Options
(a) T/8
(b) T/12
(c) T/2
(d) T/4
Correct Answer:
T/12
Explanation:
Displacement from the mean position y = a sin(2π / T) t
According to the problem y = a/2
a/2 = a sin (2π / T) t
⇒ π / 6 = (2π / T) t ⇒ t = T / 12
This is the minimum time taken by the particle to travel half of the amplitude from the equilibrium position.
Related Questions: - A transverse wave is represented by y = a sin (?t – kx)
- In producing chlorine through electrolysis 100 watt power at 1125 V is being
- A parallel beam of light of wavelength λ is incident normally on a narrow slit
- If force(F),length(L) and time(T) be considered fundamental units, then the units of mass
- A neutron moving with velocity v collides with a stationary particle
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A transverse wave is represented by y = a sin (?t – kx)
- In producing chlorine through electrolysis 100 watt power at 1125 V is being
- A parallel beam of light of wavelength λ is incident normally on a narrow slit
- If force(F),length(L) and time(T) be considered fundamental units, then the units of mass
- A neutron moving with velocity v collides with a stationary particle
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply