| ⇦ | 
| ⇨ |
The root mean square speed of oxygen molecule (O₂) at a certain temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the rms speed would be
Options
(a) v
(b) √2 v
(c) 2v
(d) 2√2 v
Correct Answer:
2v
Explanation:
The rms speed is given by
v(rms) = √(3RT / M)
[v(rms)]o₂ = √(3RT / M) = √(3RT / M) = v
[v(rms)]o = √[3R(2T) / M] = 2 √(3RT / M) = 2v
Related Questions: - A body projected vertically from the earth reaches a height equal to earth’s radius
- A capacitor of capacitance value 1 μF is charged to 30 V and the battery
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- On adjusting the P-N junction diode in forward bias,
- A body of mass 2 kg is moved by a force F=3x where x is the distance covered.
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body projected vertically from the earth reaches a height equal to earth’s radius
- A capacitor of capacitance value 1 μF is charged to 30 V and the battery
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- On adjusting the P-N junction diode in forward bias,
- A body of mass 2 kg is moved by a force F=3x where x is the distance covered.
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply