| ⇦ | 
| ⇨ |
The root mean square speed of oxygen molecule (O₂) at a certain temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the rms speed would be
Options
(a) v
(b) √2 v
(c) 2v
(d) 2√2 v
Correct Answer:
2v
Explanation:
The rms speed is given by
v(rms) = √(3RT / M)
[v(rms)]o₂ = √(3RT / M) = √(3RT / M) = v
[v(rms)]o = √[3R(2T) / M] = 2 √(3RT / M) = 2v
Related Questions: - Across a metallic conductor of non-uniform cross-section, a constant potential
- A particle executing simple harmonic motion of amplitude 5 cm has maximum
- The polarising angle of glass is 57⁰. A ray of light which is incident at this angle
- Steam at 100⁰C is passed into 20 g of water at 10°C. When water acquires a temperature
- In cyclotron, for a given magnet, radius of the semicircle traced by positive ion
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Across a metallic conductor of non-uniform cross-section, a constant potential
- A particle executing simple harmonic motion of amplitude 5 cm has maximum
- The polarising angle of glass is 57⁰. A ray of light which is incident at this angle
- Steam at 100⁰C is passed into 20 g of water at 10°C. When water acquires a temperature
- In cyclotron, for a given magnet, radius of the semicircle traced by positive ion
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply