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A thin ring of radius R meter has charge q coulomb uniformly spread on it. The ring rotates about its axis with a constant frequency of f revolutions/s. The value of magnetic induction in Wb/m² at the centre of the ring is
Options
(a) µ₀q f / 2π R
(b) µ₀q / 2π f R
(c) µ₀q / 2 f R
(d) µ₀q f / 2 R
Correct Answer:
µ₀q f / 2 R
Explanation:
Current in the ring due to the rotation,
I = q/T = q? / 2π = q.2π f / 2π
Therefore, magnetic field at the centre of the ring is
B = µ₀I / 2R = µ₀/2R . q2π f / 2π
= µ₀q f / 2 R
Related Questions: - In an NPN transistor the collector current is 24 mA. If 80% of the electrons
- 1 curie is equal to
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In an NPN transistor the collector current is 24 mA. If 80% of the electrons
- 1 curie is equal to
- 1 Wb/m² equal to
- Two bodies of mass 0.25 kg each moving towards each other with velocity
- 24 cells of emf 1.5 V each having internal resistance of 1 ohm are connected
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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