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When three identical bulbs of 60 W-200 V rating are connected in series to a 200 V supply, the power drawn by them will be
Options
(a) 60 W
(b) 180 W
(c) 10 W
(d) 20 W
Correct Answer:
20 W
Explanation:
In series, Resultant resistance = R₁ + R₂ + R₃ = R + R + R = 3R
Power = V² / R ⇒ 60 = V² / R ⇒ V² = 60 R
Power of combination = P
P = V² / Resistance of combination = 60 / 3 R = 20 W
Related Questions: - An LED is constructed from a p-n junction based on a certain semi-conducting
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An LED is constructed from a p-n junction based on a certain semi-conducting
- Two spherical conductors A and B of radii 1 mm and 2 mm are separated by a distance
- In semiconductor at a room temperature
- The upper half of an inclined plane of inclination θ is perfectly smooth while lower
- The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV,
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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