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In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduces to half. As a result the fringe width
Options
(a) is doubled
(b) is halved
(c) becomes four times
(d) remains unchanged
Correct Answer:
becomes four times
Explanation:
Fringe width β = Dλ/d;
From qn D’ = 2D and d’ = d/2
β’ = λD¹ / d¹ = 4β
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For high frequency a capacity offers
- The relationship between decay constant λ and half-life T of a radioactive substance is
- A and B are two metals with threshold frequencies 1.8 x 10¹⁴ Hz and 2.2 x 10¹⁴ Hz.
- At the first minimum adjacent to the central maximum of a single-slit diffraction
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Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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