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A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A tuning fork frequency 512 Hz is vibrated with a sonometer wire and 6 beats per second
- If rope of lift breaks suddenly, the tension exerted by the surface of the lift
- If a wire is stretched to four times its length, then the specific resistance
- A block of mass m is placed on a smooth wedge of inclination θ
- In the equation y=asin(?t+kx),the dimensionals formula of ? is
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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