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A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
- The distance travelled by a particle starting from rest and moving with an acceleration
- In which of the following heat loss is primarily not due to convection?
- A tuning fork of frequency x produces 4 beats with a source of 256 Hz and 8 beats
- When the wave of hydrogen atom comes from infinity into the first orbit,
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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