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A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
Related Questions: - A particle free to move along X-axis has potential energy given as U(X) =k(1-e⁻ˣ²)
- What is the energy released by fission of 1 g of U²³⁵?
- An electric charge 10⁻³ μC is placed at the origin (0,0) of X-Y co-ordinate system.
- A hemispherical bowl of radius R is rotating about its axis of symmetry
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle free to move along X-axis has potential energy given as U(X) =k(1-e⁻ˣ²)
- What is the energy released by fission of 1 g of U²³⁵?
- An electric charge 10⁻³ μC is placed at the origin (0,0) of X-Y co-ordinate system.
- A hemispherical bowl of radius R is rotating about its axis of symmetry
- Magnetic induction produced at the centre of a circular loop carrying current is B.
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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