| ⇦ | 
| ⇨ |
The height at which the weight of a body becomes 1/16 th, its weight on the surface of earth (radius R), is
Options
(a) 5 R
(b) 15 R
(c) 3 R
(d) 4 R
Correct Answer:
3 R
Explanation:
Let at h height, the weight of a body becomes 1/16th of its weight on the surface.
Wh = 16 Ws g’ = GM/(Re+h)²
Similarly, g = GM/Re²
Now, g’/g = Re²/(Re+h)²
⇒ g’=g(1+h/R)⁻²
⇒ Wh = 16 Ws
⇒ g’ = g/16 g’
= 16g(1+h/R)⁻² 1/16
= (1+h/R)⁻²
⇒ 4 = 1+h/R
⇒ h = 3 R
Related Questions: - If white light is used in Young’s double slit experiment
- A coil of 40 henry inductance is connected in series with a resistance of 8 ohm
- A magnifying glass of focal length 5 cm is used to view an object by a person
- A Carnot engine, having an efficiency of η=1/10 as heat engine, is used
- For a particle in a non-uniform accelerated circular motion correct statement is
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If white light is used in Young’s double slit experiment
- A coil of 40 henry inductance is connected in series with a resistance of 8 ohm
- A magnifying glass of focal length 5 cm is used to view an object by a person
- A Carnot engine, having an efficiency of η=1/10 as heat engine, is used
- For a particle in a non-uniform accelerated circular motion correct statement is
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply