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A satellite is launched into a circular orbit of radius R around earth while a second satellite is launched into an orbit of radius 1.02R. The percentage difference in the time periods of the two satellites is
Options
(a) 0.7
(b) 1
(c) 1.5
(d) 3
Correct Answer:
3
Explanation:
Apply Kepler’s third law, T²r³=constant
To study the small changes in T and r, take logs and differentiate.
2logT-3logr=log(constant)
2.dT/T-3.dr/r=zero
dT/T=3/2.dr/r
Now change in the radius of the satellite
dR=1.02R-R=0.02R
Percentage change in time period of second satellite with respect to the time period of the first satellite
dT/Tx100%=-3/2 .(0.02R)/Rx100%=3%
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Topics: Gravitation
(63)
Subject: Physics
(2479)
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