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When a sound wave of wavelength λ is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is
Options
(a) λ
(b) λ/2
(c) λ/2π
(d) λ/4π
Correct Answer:
λ/2π
Explanation:
Maximum particle velocity (vₚ)ₘₐₓ = aω
where a is the amplitude of the wave and ω is the angular frequency
Wave velocity, v = λʋ
where λ is the wavelength of a wave and ʋ is a frequency of a wave.
Given : vₚ = v .·. aω = λʋ or a × 2πʋ = λʋ or a = λ/2π
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electric dipole of length 1 cm is placed with the axis making an angle of 30⁰
- A nucleus ᵐₙ X emits one α- particle and two β- particles. The resulting nucleus is
- Number of electrons in one mC charge, given e=1.6×10⁻¹⁹ C, will be
- A thin semicircular conducting ring (PQR) of radius r is falling with its plane
- In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω,
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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