| ⇦ | 
| ⇨ |
When a sound wave of wavelength λ is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is
Options
(a) λ
(b) λ/2
(c) λ/2π
(d) λ/4π
Correct Answer:
λ/2π
Explanation:
Maximum particle velocity (vₚ)ₘₐₓ = aω
where a is the amplitude of the wave and ω is the angular frequency
Wave velocity, v = λʋ
where λ is the wavelength of a wave and ʋ is a frequency of a wave.
Given : vₚ = v .·. aω = λʋ or a × 2πʋ = λʋ or a = λ/2π
Related Questions: - Two identical charges repel each other with a force equal to 10 mgwt they are 0.6 m
- The difference in the variation of resistance with temperature in a metal
- If the sodium light in Young’s double slit experiment is replaced by red light
- The vector sum of two forces is perpendicular to their vector difference. In that case,
- A spherical body of emissivity e=0.6, placed inside a perfectly black body is maintained
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two identical charges repel each other with a force equal to 10 mgwt they are 0.6 m
- The difference in the variation of resistance with temperature in a metal
- If the sodium light in Young’s double slit experiment is replaced by red light
- The vector sum of two forces is perpendicular to their vector difference. In that case,
- A spherical body of emissivity e=0.6, placed inside a perfectly black body is maintained
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply