| ⇦ | 
| ⇨ |
A thin semicircular conducting ring (PQR) of radius r is falling with its plane vertical in a horizontal magnetic field B, as shown in the figure. The potential difference developed across the ring when its speed is v, is
Options
(a) zero
(b) Bvπr²/2 and P is at higher potential
(c) πrBv and R is at higher potential
(d) 2rBv and R is at higher potential
Correct Answer:
2rBv and R is at higher potential
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The photoelectric threshold wevelength for potassium (work function being 2 eV) is
- A thin circular ring of mass M and radius R is rotating in a horizontal plane about
- The ratio of the weight of a man in a stationary lift and when it is moving downwards
- A rocket with a lift-off mass 3.5 x 10⁴ kg is blasted upwards with an initial acceleration
- A boy standing at top of a tower of 20 m height drops a stone
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The photoelectric threshold wevelength for potassium (work function being 2 eV) is
- A thin circular ring of mass M and radius R is rotating in a horizontal plane about
- The ratio of the weight of a man in a stationary lift and when it is moving downwards
- A rocket with a lift-off mass 3.5 x 10⁴ kg is blasted upwards with an initial acceleration
- A boy standing at top of a tower of 20 m height drops a stone
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply