| ⇦ | 
| ⇨ |
When a current of (2.5±0.5) A flows through a wire, it develops a potential difference of (20±1) V, then the resistance of wire is
Options
(a) (8±2)Ω
(b) (8±1.6)Ω
(c) (8±1.5)Ω
(d) (8±3)Ω
Correct Answer:
(8±2)Ω
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A drum of radius R and mass M, rolls down without slipping along an inclined plane
- A capacitor is used to store 24 watt hour of energy at 1200 volt.
- A plank with a box on it at one end is gradually raised about the other end.
- A body is thrown upward from ground covers equal distances
- After 300 days, the activity of a radioactive sample is 5000 dps
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A drum of radius R and mass M, rolls down without slipping along an inclined plane
- A capacitor is used to store 24 watt hour of energy at 1200 volt.
- A plank with a box on it at one end is gradually raised about the other end.
- A body is thrown upward from ground covers equal distances
- After 300 days, the activity of a radioactive sample is 5000 dps
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
R=V/I
R=20/2.5
R= 8 ohm
Now,
∆ R/R=∆ V/V+∆I/I
=1/20 +0.5/2.5
= 1/4
Therefore,
∆ R÷R=1÷4
∆ R=1÷4×R
∆R=1÷4×8
∆R=2
Therefore,
Resistance with error limits=R+ – ∆R
=(8+ – 2)ohm