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When a sound wave of wavelength λ is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is
Options
(a) λ
(b) λ/2
(c) λ/2π
(d) λ/4π
Correct Answer:
λ/2π
Explanation:
Maximum particle velocity (vₚ)ₘₐₓ = aω
where a is the amplitude of the wave and ω is the angular frequency
Wave velocity, v = λʋ
where λ is the wavelength of a wave and ʋ is a frequency of a wave.
Given : vₚ = v .·. aω = λʋ or a × 2πʋ = λʋ or a = λ/2π
Related Questions: - Which of the following does not increase regularly?
- The de-Broglie wavelength of an electron in the first Bohr orbit is
- A thin circular ring of mass M and radius R rotates about an axis through its centre
- Thomson coefficient of a conductor is 10 µV/K. Its two ends are kept
- The escape velocity from the earth is Ve. The escape velocity from a planet
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following does not increase regularly?
- The de-Broglie wavelength of an electron in the first Bohr orbit is
- A thin circular ring of mass M and radius R rotates about an axis through its centre
- Thomson coefficient of a conductor is 10 µV/K. Its two ends are kept
- The escape velocity from the earth is Ve. The escape velocity from a planet
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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