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Two closed organ pipes when sounded simultaneously give 4 beats/second. If longer pipe has a length of 1m, then length of shorter pipe will be (v=300 m/s)
Options
(a) 185.5 cm
(b) 94.9 cm
(c) 90 cm
(d) 80 cm
Correct Answer:
94.9 cm
Explanation:
n₂ – n₁ = 4, For closed pipe, n = V/4l
(V/4l₂) – (V/4l₁) = 4 ⇒ (V/4l₂) – (V/4×1) = 4
(300/4l₂) – (300/4) = 4 ⇒ 75/l₂ = 4 + 75 ⇒ 75/l₂ = 79
⇒ l₂ = (75/79) met = (75×100)/79 = 94.9 cm.
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å
- Two tangent galvanometers A and B have coils of radii 8 cm and 16 cm respectively
- The minimum wavelength of X-rays produced in a Collidge tube operated
- A particle executing simple harmonic motion of amplitude 5 cm has maximum
- A source of sound S emitting waves of frequency 100 Hz and an observer
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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