| ⇦ | 
| ⇨ |
If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum intensity and minimum intensity is
Options
(a) (9:1)
(b) (1:9)
(c) (4:1)
(d) (1:4)
Correct Answer:
(9:1)
Explanation:
Let ɑ and b the amplitude of wave.
Given: ɑ / b = 2 / 1 (or) ɑ = 2b
I(max) / I(min) = (ɑ + b)² / (ɑ – b)² = 9 / 1
Related Questions: - For the action of a common Base (CB) transistor, (E=emitter, B= base, C= collector)
- A Si and a Ge diode has identical physical dimensions. The bandgap in Si is larger
- When an α-particle of mass m moving with velocity ν bombards on a heavy nucleus
- The de-Broglie wavelength of an electron moving with a velocity 1.5×10⁸ ms⁻¹ is equal
- Which of the following combinations should be selected for better tuning of an L-C-R
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For the action of a common Base (CB) transistor, (E=emitter, B= base, C= collector)
- A Si and a Ge diode has identical physical dimensions. The bandgap in Si is larger
- When an α-particle of mass m moving with velocity ν bombards on a heavy nucleus
- The de-Broglie wavelength of an electron moving with a velocity 1.5×10⁸ ms⁻¹ is equal
- Which of the following combinations should be selected for better tuning of an L-C-R
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply