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If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum intensity and minimum intensity is
Options
(a) (9:1)
(b) (1:9)
(c) (4:1)
(d) (1:4)
Correct Answer:
(9:1)
Explanation:
Let ɑ and b the amplitude of wave.
Given: ɑ / b = 2 / 1 (or) ɑ = 2b
I(max) / I(min) = (ɑ + b)² / (ɑ – b)² = 9 / 1
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The total energy of a simple harmonic oscillator is proportional to
- When the angle of incidence is 60° on the surface of a glass slab, it is found
- Point masses m₁ and m₂ are placed at the opposite ends of a rigid rod of length L,
- A source of unknown frequency gives 4 beats/s, when sounded with a source harmonic
- The particle executing simple harmonic motion has a kinetic energy K₀cos²ωt.
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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