| ⇦ | 
| ⇨ |
A p-n photodiode is made of a material with a band gap of 2.0 eV. The minimum frequency of the radiation that can be absorbed by the material is nearly
Options
(a) 10 x 10¹⁴ Hz
(b) 5 x 10¹⁴ Hz
(c) 1 x 10¹⁴ Hz
(d) 20 x 10¹⁴ Hz
Correct Answer:
5 x 10¹⁴ Hz
Explanation:
Eₑ = 2.0 eV = 2 x 1.6 x 10⁻¹⁹ J
Eₑ = hv v = Eₑ/h = 2 x 1.6 x 10⁻¹⁹ J / 6.62 x 10⁻³⁴ Js
= 0.4833 x 10¹⁵ s⁻¹ = 4.833 x 10¹⁴ Hz
app. 5 x 10¹⁴ Hz
Related Questions: - In common base mode of a transistor, the collector current is 5.488 mA
- Two closed organ pipes when sounded simultaneously give 4 beats/second.
- In the elastic collision of objects
- ₆C¹⁴ absorbs an energitic neutron and emits beta particles. The resulting nucleus is
- Force required to move a mass of 1kg at rest on a horizontal rough plane
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In common base mode of a transistor, the collector current is 5.488 mA
- Two closed organ pipes when sounded simultaneously give 4 beats/second.
- In the elastic collision of objects
- ₆C¹⁴ absorbs an energitic neutron and emits beta particles. The resulting nucleus is
- Force required to move a mass of 1kg at rest on a horizontal rough plane
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply