| ⇦ | 
| ⇨ |
The current through an inductor changes from 3 A to 2 A is 1 m/s. If induced e.m.f. in inductor is 5V then L is
Options
(a) 5×10⁻² H
(b) 5×10⁻³ H
(c) 2.5×10⁻³ H
(d) None of these
Correct Answer:
5×10⁻³ H
Explanation:
– L (di / dt) = ε ⇒ L × [(3A – 2A) / (i × 10⁻³s)] = 5 V
Therefore, L = 5 × 10⁻³ H
Related Questions: - Which one of the following electrical meter has the smallest resistance?
- A compass needle which is allowed to move in a horizontal plane
- A bomb of mass 30 kg at rest exploded into two pieces of masses 18 kg
- A capacitor of 10 µF charged upto 250 volt is connected in parallel with another
- The kinetic energy of α-particle emitted in the α-dacay of ₈₈Ra²²⁶ is
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following electrical meter has the smallest resistance?
- A compass needle which is allowed to move in a horizontal plane
- A bomb of mass 30 kg at rest exploded into two pieces of masses 18 kg
- A capacitor of 10 µF charged upto 250 volt is connected in parallel with another
- The kinetic energy of α-particle emitted in the α-dacay of ₈₈Ra²²⁶ is
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply