| ⇦ | 
| ⇨ |
The current through an inductor changes from 3 A to 2 A is 1 m/s. If induced e.m.f. in inductor is 5V then L is
Options
(a) 5×10⁻² H
(b) 5×10⁻³ H
(c) 2.5×10⁻³ H
(d) None of these
Correct Answer:
5×10⁻³ H
Explanation:
– L (di / dt) = ε ⇒ L × [(3A – 2A) / (i × 10⁻³s)] = 5 V
Therefore, L = 5 × 10⁻³ H
Related Questions: - A wire of one metre length carries a constant current. The wire is bent to form
- The radius of the convex surface of a plano-convex lens is 20 cm and the refractive index
- A wire of a certain material is stretched slowly by ten percent. Its new resistance
- By the succesive disintegration of ₉₂U²³⁸, the final product obtained is ₈₂Pb²⁰⁶, then
- A particle is moving such that its position coordinates (x,y) are (2 m,3 m) at time
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire of one metre length carries a constant current. The wire is bent to form
- The radius of the convex surface of a plano-convex lens is 20 cm and the refractive index
- A wire of a certain material is stretched slowly by ten percent. Its new resistance
- By the succesive disintegration of ₉₂U²³⁸, the final product obtained is ₈₂Pb²⁰⁶, then
- A particle is moving such that its position coordinates (x,y) are (2 m,3 m) at time
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply