| ⇦ | 
| ⇨ |
The current through an inductor changes from 3 A to 2 A is 1 m/s. If induced e.m.f. in inductor is 5V then L is
Options
(a) 5×10⁻² H
(b) 5×10⁻³ H
(c) 2.5×10⁻³ H
(d) None of these
Correct Answer:
5×10⁻³ H
Explanation:
– L (di / dt) = ε ⇒ L × [(3A – 2A) / (i × 10⁻³s)] = 5 V
Therefore, L = 5 × 10⁻³ H
Related Questions: - For the action of a common Base (CB) transistor, (E=emitter, B= base, C= collector)
- A gaussian sphere encloses an electric dipole within it. The total flux
- The energy of groundstate (n=1) of hydrogen level is -13.6 eV. The ionistation
- An inclined plane makes an angle of 30° with the horizontal.A solid sphere
- If the binding energy of the electron in a hydrogen atom is 13.6 eV, the energy
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For the action of a common Base (CB) transistor, (E=emitter, B= base, C= collector)
- A gaussian sphere encloses an electric dipole within it. The total flux
- The energy of groundstate (n=1) of hydrogen level is -13.6 eV. The ionistation
- An inclined plane makes an angle of 30° with the horizontal.A solid sphere
- If the binding energy of the electron in a hydrogen atom is 13.6 eV, the energy
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply