| ⇦ | 
| ⇨ |
The current through an inductor changes from 3 A to 2 A is 1 m/s. If induced e.m.f. in inductor is 5V then L is
Options
(a) 5×10⁻² H
(b) 5×10⁻³ H
(c) 2.5×10⁻³ H
(d) None of these
Correct Answer:
5×10⁻³ H
Explanation:
– L (di / dt) = ε ⇒ L × [(3A – 2A) / (i × 10⁻³s)] = 5 V
Therefore, L = 5 × 10⁻³ H
Related Questions: - RMS velocity of gas is proportional to
- If the kinetic energy of the particle is increased to 16 times its previous value
- Dimensional formula for electrical resistance R is given by
- The ratio of amplitude of magnetic field to the amplitude of electric field for
- A ball is dropped from a high rise platform at t = 0 starting from rest
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- RMS velocity of gas is proportional to
- If the kinetic energy of the particle is increased to 16 times its previous value
- Dimensional formula for electrical resistance R is given by
- The ratio of amplitude of magnetic field to the amplitude of electric field for
- A ball is dropped from a high rise platform at t = 0 starting from rest
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply