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The self induced e.m.f. in a 0.1 H coil when the current in it is changing at the rate of 200 amp/sec is
Options
(a) 8×10⁻⁴ V
(b) 8×10⁻⁵ V
(c) 20 V
(d) 125 V
Correct Answer:
20 V
Explanation:
e = – L (dI / dt), Magnitude of e = L (dI / dt) = 0.1 × 200 = 20 V
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At place on earth, the vertical component of earth’s magnetic field is √3 times
- The electirc field in a certain region is acting radially outward and is given by E=Ar.
- A particle of mass m executes simple harmonic motion with amplitude
- If the cold junction of a thermo-couple is kept at 0⁰C and the hot junction is kept
- An electric dipole of moment ‘p’ is placed in an elecatric field of intensity ‘E’
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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