⇦ | ⇨ |
The self induced e.m.f. in a 0.1 H coil when the current in it is changing at the rate of 200 amp/sec is
Options
(a) 8×10⁻⁴ V
(b) 8×10⁻⁵ V
(c) 20 V
(d) 125 V
Correct Answer:
20 V
Explanation:
e = – L (dI / dt), Magnitude of e = L (dI / dt) = 0.1 × 200 = 20 V
Related Questions: - When germanium is doped with phosphorus what type of semiconductor is produced?
- Rutherford’s ∝ particle experiment showed that the atoms have
- Parsec is the unit of
- The instantaneous values of alternating current and voltages in a circuit are given as
- Three unequal resistors in parallel are equivalent to a resistance 1 Ω.
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When germanium is doped with phosphorus what type of semiconductor is produced?
- Rutherford’s ∝ particle experiment showed that the atoms have
- Parsec is the unit of
- The instantaneous values of alternating current and voltages in a circuit are given as
- Three unequal resistors in parallel are equivalent to a resistance 1 Ω.
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply