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The self induced e.m.f. in a 0.1 H coil when the current in it is changing at the rate of 200 amp/sec is
Options
(a) 8×10⁻⁴ V
(b) 8×10⁻⁵ V
(c) 20 V
(d) 125 V
Correct Answer:
20 V
Explanation:
e = – L (dI / dt), Magnitude of e = L (dI / dt) = 0.1 × 200 = 20 V
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The magnetic field due to a current carrying circular loop of radius 3 cm at a point
- A 1 µA beam of protons with a cross-sectional area of 0.5 sq.mm is moving with a velocity
- In stretching a spring by 2 cm, energy stored is given by U. Had is been stretched
- A polished metal plate has a rough and black-spot. It is heated to 1400 K
- A cylindrical tank is filled with water to a level of 3m. A hole is opened at a height
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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