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The self induced e.m.f. in a 0.1 H coil when the current in it is changing at the rate of 200 amp/sec is
Options
(a) 8×10⁻⁴ V
(b) 8×10⁻⁵ V
(c) 20 V
(d) 125 V
Correct Answer:
20 V
Explanation:
e = – L (dI / dt), Magnitude of e = L (dI / dt) = 0.1 × 200 = 20 V
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A galvanometer acting as a voltmeter will have
- A galvanometer having resistance of 50 Ω requires a current of 100μA to give full
- A juggler maintains four balls in motion,making each of them to rise
- In India, electricity is supplied for domestic use at 200V. It is supplied at 110 V
- A body of mass m is thrown upwards at an angle θ with the horizontal with velocity
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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