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λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe widths. The wavelength λ₁ can produce photoelectric effect when incident on a metal. But the wavelength λ₂ cannot produce photoelectric effect. The correct relation between β₁ and β₂ is
Options
(a) β₁ < β₂
(b) β₁ = β₂
(c) β₁ > β₂
(d) β₁ ≥ β₂
Correct Answer:
β₁ < β₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The de-Broglie wavelength of an electron in the first Bohr orbit is
- A capacitor of 2.5 μF is charged through a resistor of 4 MΩ. In how much time
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- A block of mass 4 kg is kept on a rough horizontal surface.The coefficient of static
- The work of 146 kJ is performed in order to compress one kilo mole fo gas adiabatically
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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