| ⇦ | 
| ⇨ |
λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe widths. The wavelength λ₁ can produce photoelectric effect when incident on a metal. But the wavelength λ₂ cannot produce photoelectric effect. The correct relation between β₁ and β₂ is
Options
(a) β₁ < β₂
(b) β₁ = β₂
(c) β₁ > β₂
(d) β₁ ≥ β₂
Correct Answer:
β₁ < β₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A common emitter amplifier gives an output of 3 V for an input of 0.01 V.
- An experiment takes 10 minutes to raise temperature of water from 0⁰C to 100⁰C
- The de-Broglie wavelength of an electron in the first Bohr orbit is
- The electric current in AC circuit is given by the relation i-3 sinωt+4 cos ωt.
- A liquid boils when its vapour pressure equals
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A common emitter amplifier gives an output of 3 V for an input of 0.01 V.
- An experiment takes 10 minutes to raise temperature of water from 0⁰C to 100⁰C
- The de-Broglie wavelength of an electron in the first Bohr orbit is
- The electric current in AC circuit is given by the relation i-3 sinωt+4 cos ωt.
- A liquid boils when its vapour pressure equals
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply